Optimal. Leaf size=92 \[ \frac{i b \text{PolyLog}\left (2,-i e^{i \left (c+d x^2\right )}\right )}{2 d^2}-\frac{i b \text{PolyLog}\left (2,i e^{i \left (c+d x^2\right )}\right )}{2 d^2}+\frac{a x^4}{4}-\frac{i b x^2 \tan ^{-1}\left (e^{i \left (c+d x^2\right )}\right )}{d} \]
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Rubi [A] time = 0.0877414, antiderivative size = 92, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.312, Rules used = {14, 4204, 4181, 2279, 2391} \[ \frac{i b \text{PolyLog}\left (2,-i e^{i \left (c+d x^2\right )}\right )}{2 d^2}-\frac{i b \text{PolyLog}\left (2,i e^{i \left (c+d x^2\right )}\right )}{2 d^2}+\frac{a x^4}{4}-\frac{i b x^2 \tan ^{-1}\left (e^{i \left (c+d x^2\right )}\right )}{d} \]
Antiderivative was successfully verified.
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Rule 14
Rule 4204
Rule 4181
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int x^3 \left (a+b \sec \left (c+d x^2\right )\right ) \, dx &=\int \left (a x^3+b x^3 \sec \left (c+d x^2\right )\right ) \, dx\\ &=\frac{a x^4}{4}+b \int x^3 \sec \left (c+d x^2\right ) \, dx\\ &=\frac{a x^4}{4}+\frac{1}{2} b \operatorname{Subst}\left (\int x \sec (c+d x) \, dx,x,x^2\right )\\ &=\frac{a x^4}{4}-\frac{i b x^2 \tan ^{-1}\left (e^{i \left (c+d x^2\right )}\right )}{d}-\frac{b \operatorname{Subst}\left (\int \log \left (1-i e^{i (c+d x)}\right ) \, dx,x,x^2\right )}{2 d}+\frac{b \operatorname{Subst}\left (\int \log \left (1+i e^{i (c+d x)}\right ) \, dx,x,x^2\right )}{2 d}\\ &=\frac{a x^4}{4}-\frac{i b x^2 \tan ^{-1}\left (e^{i \left (c+d x^2\right )}\right )}{d}+\frac{(i b) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{i \left (c+d x^2\right )}\right )}{2 d^2}-\frac{(i b) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{i \left (c+d x^2\right )}\right )}{2 d^2}\\ &=\frac{a x^4}{4}-\frac{i b x^2 \tan ^{-1}\left (e^{i \left (c+d x^2\right )}\right )}{d}+\frac{i b \text{Li}_2\left (-i e^{i \left (c+d x^2\right )}\right )}{2 d^2}-\frac{i b \text{Li}_2\left (i e^{i \left (c+d x^2\right )}\right )}{2 d^2}\\ \end{align*}
Mathematica [A] time = 0.0209784, size = 95, normalized size = 1.03 \[ \frac{i b \text{PolyLog}\left (2,-i e^{i \left (c+d x^2\right )}\right )}{2 d^2}-\frac{i b \text{PolyLog}\left (2,i e^{i \left (c+d x^2\right )}\right )}{2 d^2}+\frac{a x^4}{4}-\frac{i b x^2 \tan ^{-1}\left (e^{i c+i d x^2}\right )}{d} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.092, size = 0, normalized size = 0. \begin{align*} \int{x}^{3} \left ( a+b\sec \left ( d{x}^{2}+c \right ) \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{4} \, a x^{4} + 2 \, b \int \frac{x^{3} \cos \left (2 \, d x^{2} + 2 \, c\right ) \cos \left (d x^{2} + c\right ) + x^{3} \sin \left (2 \, d x^{2} + 2 \, c\right ) \sin \left (d x^{2} + c\right ) + x^{3} \cos \left (d x^{2} + c\right )}{\cos \left (2 \, d x^{2} + 2 \, c\right )^{2} + \sin \left (2 \, d x^{2} + 2 \, c\right )^{2} + 2 \, \cos \left (2 \, d x^{2} + 2 \, c\right ) + 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.99405, size = 884, normalized size = 9.61 \begin{align*} \frac{a d^{2} x^{4} - b c \log \left (\cos \left (d x^{2} + c\right ) + i \, \sin \left (d x^{2} + c\right ) + i\right ) + b c \log \left (\cos \left (d x^{2} + c\right ) - i \, \sin \left (d x^{2} + c\right ) + i\right ) - b c \log \left (-\cos \left (d x^{2} + c\right ) + i \, \sin \left (d x^{2} + c\right ) + i\right ) + b c \log \left (-\cos \left (d x^{2} + c\right ) - i \, \sin \left (d x^{2} + c\right ) + i\right ) - i \, b{\rm Li}_2\left (i \, \cos \left (d x^{2} + c\right ) + \sin \left (d x^{2} + c\right )\right ) - i \, b{\rm Li}_2\left (i \, \cos \left (d x^{2} + c\right ) - \sin \left (d x^{2} + c\right )\right ) + i \, b{\rm Li}_2\left (-i \, \cos \left (d x^{2} + c\right ) + \sin \left (d x^{2} + c\right )\right ) + i \, b{\rm Li}_2\left (-i \, \cos \left (d x^{2} + c\right ) - \sin \left (d x^{2} + c\right )\right ) +{\left (b d x^{2} + b c\right )} \log \left (i \, \cos \left (d x^{2} + c\right ) + \sin \left (d x^{2} + c\right ) + 1\right ) -{\left (b d x^{2} + b c\right )} \log \left (i \, \cos \left (d x^{2} + c\right ) - \sin \left (d x^{2} + c\right ) + 1\right ) +{\left (b d x^{2} + b c\right )} \log \left (-i \, \cos \left (d x^{2} + c\right ) + \sin \left (d x^{2} + c\right ) + 1\right ) -{\left (b d x^{2} + b c\right )} \log \left (-i \, \cos \left (d x^{2} + c\right ) - \sin \left (d x^{2} + c\right ) + 1\right )}{4 \, d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{3} \left (a + b \sec{\left (c + d x^{2} \right )}\right )\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sec \left (d x^{2} + c\right ) + a\right )} x^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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